factorise:(a+3c)³+(2a-c)³-(3a+2c)³
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(a+3c)³+(2a-c)³-(3a+2c)³
=(a+3c)³+(2a-c)³+(-3a-2c)³
=3(a+3c)(2a-c)(-3a-2c)
=3(a+3c)(c-2a)(3a+2c)
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