Question

factorise a^3x+a^2(x-y)-a(y+z) -z

Answer 1

$\textbf{Answer :}$

Now,

a³x + a² (x - y) - a (y + z) - z

= a³x + a²x - a²y - ay - az - z

= a²x (a + 1) - ay (a + 1) + z (a + 1)

= (a + 1) (a²x - ay + z),

which is the required factorization.

#$\texttt{MarkAsBrainliest}$

Answer 2

As per the data given in the above question

We have to find the factorisation of given equation.

Step-by-step explanation:

Given ,

$a^3x+a^2(x-y)-a(y+z) -z$

Step -1

According to BODMAS solve the bracket ,

$a^3x+a^2x- {a}^{2} y-ay - az -z$

Step-2

Seperate the variable of x ,y and z and it will change the sign

$(a^3x+a^2x)-( {a}^{2} y + ay) - (az + z)$

Step-3

Take out the common term from each term,

$a^2x(a+1)- ay(a + 1) -z(a + 1)$

Step-4

In each term same common term is out , then

$(a + 1) \: (a^2x- ay -z)$

Hence ,

The factorisation is

$a^3x+a^2(x-y)-a(y+z) -z= \\ (a + 1) \: (a^2x- ay -z)$

Project code #SPJ3