Question

factorise a^4+4a^2b^2+4b^4-c^4

Answer 1

Solution

Factorization is so easy in algebra.

Just follow the given step carefully.

${a}^{4} + 4 {a}^{2} {b}^{2} + 4 {b}^{2} - {c}^{4} \\ \\ {[ {a}^{2} + {b}^{2} ]}^{2} - {c}^{4} \: \: \: [Using \: x^2+ 2xy + y^2 = (x + y)^2]$

${[ {a}^{2} + {b}^{2} ]}^{2} - {c}^{4} \\ ( {a}^{2} + {b}^{2} + {c}^{2} )( {a}^{2} + {b}^{2} - {c}^{2} ) \: \: \: \: [Using \: \ {x}^{2} - {y}^{2} = (x+y)(x - y)]$

Answer 2

Answer:

is it visible

Step-by-step explanation:

the answer is up