Question

factorise: a^6-7a^3-8

Answer 1

a^6 + a^3 - 8a^3 - 8

= a^3 ( a^3 + 1) - 8 ( a^3 + 1)

= (a^3 - 8)(a^3 + 1)

= [ (a)^3 - (2)^3] [ (a)^3 +(1)^3]

= (a-2)(a^2 + 2a + 4)(a+1)(a^2 - a + 1)

Answer 2

Answer:

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