Question

Factorise
a(a+b)^3 - 3a^2b(a+b)
Please solve this its answer comes
a(a+b) (a^2+b^2-ab)

Answer 1

Take ( a + b ) common first --

( a + b ) [ a ( a + b ) ^ 2 - 3a b ]

= ( a + b ) [ a ( a ^ 2 + b ^2 + 2ab) - 3ab ]

= a ( a + b ) [ a ^ 2 + b ^2 + 2ab - 3ab ]

= a ( a + b ) (a ^ 2 + b ^ 2 - ab )

Answer 2

take a(a+b) common --

a(a+b)[(a+b)^2-3ab]

= a(a+b)(a^2+b^2+2ab-3ab)

= a(a+b)(a^2+b^2-ab)