factorise a(a+b-c) -bc
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your answer is in the referred attachment.
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Answered by
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a(a+b+c) - bc
>a^2+ ab+ac-bc
>a^2 +a(b+c) -bc
Here , if we compare the above statement with standard quadratic equation we get
a=1, b=(b+c) c= (-bc)
by quadratic formula
(-b +- √b²-4ac)/2a
the calculation is done in the above image
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