Question

Factorise (a + b)^3 - 8

Answer 1

= > ( a + b )³- 8

= > ( a + b )³ - 2³


by formula a^3 - b^3 = ( a - b ) ( a² + ab + b² )


here,  (a+b)^3 - 2³

[ a + b - 2 ][ ( a + b )^2 + 2^2 + 2( a + b ) ]

[ a + b - 2 ][ a^2 + b^2 + 2ab + 2 + 2a + b ]

[ a + b - 2 ][ a^2 + a + b^2 + c + 2ab + 2 ]

Answer 2

(a+b)^3-2^3=(a+b-2)[(a+b)^2+4-2a+2b]
hope that mine is correct.....plz mark as brainliest
please feel free to ask doubts to me......