Question

factorise(a+b)3-8
please solve it out.........

Answer 1

This should be your answer.

Answer 2

Answer:

$(a+b)^3-8=(a+b-2)((a+b)^2+2(a+b)+2^2)$

Step-by-step explanation:

Given the polynomial

$(a+b)^3-8$

we have to factorize the above polynomial.

Using identity

$x^3-y^3=(x-y)(x^2+xy+y^2)$

$(a+b)^3-8$

$=(a+b)^3-2^3$

Put x=a+b, y=2

$=(a+b-2)((a+b)^2+2(a+b)+2^2)$