Factorise (a+b)^3-a-b
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(a+b)³-(a+b)
Taking out (a+b) as common ,
(a+b)[(a+b)²-1]
(a+b)[(a+b)²-(1)²]
(a+b)(a+b+1)(a+b-1)
Taking out (a+b) as common ,
(a+b)[(a+b)²-1]
(a+b)[(a+b)²-(1)²]
(a+b)(a+b+1)(a+b-1)
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