Factorise(a-b)+(a^2-b^2)
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We have,
![\quad \: (a - b) + ( {a}^{2} - {b}^{2} ) \\ \\ = (a - b) + \left[ (a - b)(a + b) \right] \\ \\ = (a - b) \left[ 1 + (a + b) \right] \\ \\ = \bf(a - b)(a + b + 1)](https://tex.z-dn.net/?f=+%5Cquad+%5C%3A+%28a+-+b%29+%2B+%28+%7Ba%7D%5E%7B2%7D+-+%7Bb%7D%5E%7B2%7D+%29+%5C%5C+%5C%5C+%3D+%28a+-+b%29+%2B+%5Cleft%5B+%28a+-+b%29%28a+%2B+b%29+%5Cright%5D+%5C%5C+%5C%5C+%3D+%28a+-+b%29+%5Cleft%5B+1+%2B+%28a+%2B+b%29+%5Cright%5D+%5C%5C+%5C%5C+%3D+%5Cbf%28a+-+b%29%28a+%2B+b+%2B+1%29 "\quad \: (a - b) + ( {a}^{2} - {b}^{2} ) \\ \\ = (a - b) + \left[ (a - b)(a + b) \right] \\ \\ = (a - b) \left[ 1 + (a + b) \right] \\ \\ = \bf(a - b)(a + b + 1)")
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0
Answer:
We have,
$$\begin{lgathered}\quad \: (a - b) + ( {a}^{2} - {b}^{2} ) \\ \\ = (a - b) + \left[ (a - b)(a + b) \right] \\ \\ = (a - b) \left[ 1 + (a + b) \right] \\ \\ = \bf(a - b)(a + b + 1)\end{lgathered}$$
$$\mid \underline{\underline{\LARGE\bf\green{Brainliest \: Answer}}}\mid$$
Thank you❤
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