Question

factorise:(a/b+b/a)+(b/c+c/b)+(c/a+a/c)+3. plz help

Answer 1

Answer:

( ab + bc + ac ) ( a + b + c ) / abc

Step-by-step explanation:

( a / b + b / a ) + ( b / c + c / b ) + ( c / a + a / c ) + 3

==> ( a² + b² ) / ab + ( b² + c² )/ bc + ( c² + a² )/ac + 3

==> ( c (a² + b²) + a( b² + c² ) + b ( a² + c² ) ) / abc + 3

==> ( a²c + b²c + ab² + ac² + a²b + c²b ) / abc + 3

==> ( a²c + ac² + b²c + bc² + a²b + ab² ) / abc + 3

==> ( a²c + ac² + b²c + bc² + a²b + ab² + 3 abc ) / abc

==> ( a²c + ac² +abc + b²c + bc² +abc + a²b + ab² + abc ) / abc

==> ( ac ( a + c + b ) + bc ( b + c + a ) + ab ( a + b + c ) )/ abc

==> ( ab + bc + ac ) ( a + b + c ) / abc

Thats the factorised answer

Hope it helps ya :)

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Answer 2

answer is
(a+b+c)(ab+bc+ac)÷abc