Question

factorise
(a+b-c)^2-(a-b+c)^2​

Answer 1

Answer:

4c(a+b) is the answer

Step-by-step explanation:

(a + b + c)2 - (a + b - c)2 = 2a + 2b + 2c - 2a - 2b + 2c = 4c

Someone else suggested that the numbers may be indices, the correct notation for that would be: (a + b + c)^2 - (a + b - c)^2. I guess I may as well do that one:

(a + b + c)^2 - (a + b - c)^2

= (a^2 + b^2 + c^2 + 2ab + 2ac + 2bc) - (a^2 + b^2 + c^2 + 2ab - 2ac - 2bc)

= 4ac + 4bc

=4c(a + b)