Question

factorise (a+b)cube+(b+C)cube+(a+C)-3(a+b)(b+c)(a+c)

Answer 1

Step-by-step explanation:

step 1: assign variable

let (a+b) be x

let (b+c) be y

let (a+d) be z

step:2: factorize using identity:

x³+y³+z³- 3xyz = (x+y+z)(x²+y²+z²-xy -yz - xz)

= (x+y+z)(x²+y²+z²-xy -yz - xz)

step:3: final answer

((a+b)+(c+b)+(a+c))(((a+b)²+(c+b)²+(a+c)²-(a+b)(c+b)-(c+b)(a+c)-(a+c)(a+b))

Answer 2

Answer:

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