Question

Factorise a cube + 64 b cube + 14 a square b + 56 a b square

Answer 1

Answer:

α³+64b³+14a²b+56αb²= (a+b)³

Step-by-step explanation:

$a^{3} + 64 b^{3}+ 14 a^{2} b  + 56ab^{2} \\∵(x+y)^{2} =x^{3}+y^{3}+3x^{2} y+3xy^{2}  (identity)\\∴x=a,\\∴y=4b\\∴a^{3} + 64 b^{3}+ 14 a^{2} b  + 56ab^{2}= (a+4b)^{3}$