factorise: a cube-8b cube-2ax+4bx
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13
Solution :
a³ - 8b³ - 2ax + 4bx
= [a³ - ( 2b )³] - 2x( a - 2b )
= (a - 2b)[a²+a×2b+(2b)²]-2x(a-2b)
= (a - 2b)[a²+2ab+4b² - 2x]
••••
a³ - 8b³ - 2ax + 4bx
= [a³ - ( 2b )³] - 2x( a - 2b )
= (a - 2b)[a²+a×2b+(2b)²]-2x(a-2b)
= (a - 2b)[a²+2ab+4b² - 2x]
••••
Answered by
1
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