Question

factorise a power6 + 8b power6 - c power6+ 6a²b²c²​

Answer 1

Step-by-step explanation:

a^6+8b^6-c^6+6a^2b^2c^2

= (a^2)^3 + (2b^2)^3 + (-c^2)^3 - 3(a^2)(2b^2)(-c^2)

= (a^2 + b^2 - c^2)[(a^2)^2 + (b^2)^2 + (-c^2)^2 - (a^2)(b^2) - (b^2)(-c^2) - (-c^2)(a^2)]

= (a^2 + b^2 + c^2) (a^4 + b^4 + c^4 - a^2b^2 - b^2c^2 - c^2a^2)