Factorise
a square (b+c) - (b+c) cube
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Answered by
1
Answer:
= b(b+c)+c(b+c)
= b²+bc+bc+c²
= b²+2bc+c²
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Answered by
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a²(b+c) - (b+c)³
==> (b+c) [a²- (b+c)²]
==> (b+c) [a²- (b²+ c²+ 2bc)]
==> (b+c) [a²-b²-c²-2bc]
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