Question

Factorise:a square +b square-2(ab-ac+bc).

Answer 1

A^2 + b^2 - 2(ab - ac +bc) = a^2 + b^2 - 2ab + 2ac - 2bc = (a- b)^2 + 2ac - 2bc [ we know that a^2 + b^2 - 2ab = (a-b)^2] = (a- b)^2 +2c (a-b) = (a- b) (a-b + ...

Answer 2

Answer:

Answer => (a - b )² + 2c(a-b)

Step-by-step explanation:

$hello \: \: yifan \: \: stan \: \: here \: u \: go \: with \: your \: answer$

Identity to keep in mind:

${(a \: - \: b \: )}^{2} = {a}^{2} + {b}^{2} - 2ab$

$given \\ {a}^{2} + {b}^{2} - 2(ab \: - ac + bc)$

$= > \: {a}^{2} + {b}^{2} - 2ac + 2ac - 2bc$

Now using the identity

$= > {(a \: - b)}^{2} + 2c(a - b) \\ = > this \: is \: the \: answer \: my \: friend$

Hope this helps you Meigeni ( Kris wu Yifan stan)

Boy or girl.... Please Mark it BRAINLIEST