Question

Factorise: a¹² b⁴-a⁴ b¹²​

Answer 1

Answer:

a⁴b⁴(a⁴+b⁴)(a²+b²)(a+b)(a-b)

Step-by-step explanation:

Using  a²−b²=(a+b)(a−b) at each step

Given:a^12b⁴−a⁴b^12

          =a⁴b⁴(a⁸−b⁸) [common]

          =a⁴b⁴[(a⁴)²−(b⁴)²]

          =a⁴b⁴(a⁴+b⁴)(a⁴−b⁴)

          =a⁴b⁴(a⁴+b⁴)[(a²)²−(b²)²]

          =a⁴b⁴(a⁴+b⁴)(a²+b²)(a²−b²)

          =a⁴b⁴(a⁴+b⁴)(a²+b²)(a+b)(a-b)

i hope this helps

Answer 2

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• I have attached two attachments here hope it may help you

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