Question

factorise: a2 - 14a - 32​

Answer 1

☆Correct question:

Factorise: a² - 14a - 32.

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☆Solution:

a² - 14a - 32

In order to factorise the given expression, we will follow the steps of splitting the middle term.

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☆Steps:

• First find the product of the first and the last term.

Here,

1a²×32 = 32 [we can ignore the variable]

• Now we will find the factors of 32.

That is,

32×1

2×16

4×8

.

.

.

• Finally, we have to find the two numbers whose sum or difference is equal to the middle term and product is equal to the product of the first and last term.

So,

As we can see that,

16-2 = 14 (middle term)

and,

16×2 = 32 (product of first and last term)

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Solution continued...:

a² - 14a - 32

a² -(16-2)a -32

a² - 16a +2a - 32

Now, we will group the terms as,

(a² - 16a) + (2a - 32)

Taking out common,

a(a-16) + 2(a-16)

Hence,

$\boxed {\sf {\purple {(a-16) (a+2)}}}$ ---> Is the final answer.

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Final answer:

The factorised form of a² - 14a - 32 is $\sf \orange {(a-16) (a+2)}$.

Answer 2

Answer:

(a-16) (a+2)

Step-by-step explanation:

if u multiply them u get the question itself