factorise a²-2ac+2bc-b²
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Answered by
1
Answer:
you put the identity (a^2-2ab+2ba-b^2)
Step-by-step explanation:
first of all you give the value of
a=??
b=??
c=??
Answered by
2
Answer:
In this equation taking common
then, a (a-2c) -b ( 2c-b)
(a-b) (a-2c) (2c-b)
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