Factorise a²-3a-108
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a^-12a+9a-108
a(a-12)-9(a-12)
(a-9)(a-12)
a(a-12)-9(a-12)
(a-9)(a-12)
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Solution
Factors of 108 = 1×108 2×54 3×36 4 × 27 18×6 12×9
As we know 12×9 suits well with our question
Therefore
a²+ 12a-9a -108
a(a+12) -9(a+12)
Factors are -
( a-9 ) ( a +12)
Through middle term splitting.
Hope the answer was helpful !
please mark it as brainleist
Factors of 108 = 1×108 2×54 3×36 4 × 27 18×6 12×9
As we know 12×9 suits well with our question
Therefore
a²+ 12a-9a -108
a(a+12) -9(a+12)
Factors are -
( a-9 ) ( a +12)
Through middle term splitting.
Hope the answer was helpful !
please mark it as brainleist
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