Question

Factorise a² +8a+15=0
​

Answer 1

Answer:

Factors \:of \:a^{2}+8a+16\\=(a+4)(a+4)

Step-by-step explanation:

Given\: expression ,a^{2}+8a+16

=a^{2}+2\times a \times 4+4^{2}\\=\left(a+4\right)^{2}

/* By algebraic identity:

\boxed { x^{2}+2xy+y^{2}=(x+y)^{2}}

=(a+4)(a+4)

Therefore,

Factors \:of \:a^{2}+8a+16\\=(a+4)(a+4)

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