Math, asked by richa2094, 9 months ago

Factorise (a2 + 9b2 - 6ab) - 4c2 ​

Answers

Answered by garaisayan46
2

{(a)^2+(3b)^2-(2×a×3b)} -4c^2

(a - 3b)^2 - (2c)^2

(a - 3b - 2c) (a - 3b + 2c)

Answered by Anonymous
0

Answer:

( {a}^{2}  + 9 {b}^{2}  - 6ab) - 4 {c}^{2}  \\ ( {a})^{2}  + (3 {b)}^{2}  - 3 \times 2ab \:  - 2 {c}^{2}  \\  (a + 3b {)}^{2}  - (2 {c})^{2} \\ (a + 3b - 2c)(a - 3b + c)

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