factorise:- a²+ab+bc+ca
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Answered by
1
Answer:
Here is the answer
let us rearrange the terms and take a and c as a the common factor
we get
= a
2
+ bc + ab + ac = a
2
+ ab + bc + ac
⇒a(a+b)+c(a+b)=(a+b)(a+c)
Answered by
0
Step-by-step explanation:
let us rearrange the terms and take a and c as a the common factor
we get
= a2 + bc + ab + ac = a2 + ab + bc + ac
⇒a(a+b)+c(a+b)=(a+b)(a+c)
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