Question

factorise a2 - (b-c )2

Answer 1

Answer:

a²-(b-c)² = (a+b-c)(a-b+c)

Explanation:

Factorising a²-(b-c)²

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we know the algebraic identity:

$\boxed {x^{2}-y^{2}=(x+y)(x-y)}$

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= [a+(b-c)][a-(b-c)]

= (a+b-c)(a-b+c)

Therefore,

a²-(b-c)² = (a+b-c)(a-b+c)

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Answer 2

Answer:(a+b-c) (a-b+c)

Step-by-step explanation:

Let (b-c) be x

a^2-x^2

(a-x) (a+x) [using a^2-b^2=(a+b) (a-b) ]

(a+b-c) (a-b+c)