Question

factorise :- a2(b+c-a)+b2(c+a-b)+c2(a+b-c)-2abc​

Answer 1

Answer:

answer

Step-by-step explanation:

(a2 +b2+c2)(a+b+c)

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Answer 2

Step-by-step explanation:

If the common difference of an A.P. is 3, then find a20 – a15.[tex] \sf \: \: \: x= \frac{(mx_2+nx_1)}{(m+n)} ,y= \frac{(my_2+ny_1)}{(m+n)} \\ \\ Given: d=3

We know:

an=a+(n−1)d

∴a20−a15=[a+19d]−[a+14d]

                     =5d

                     =5×3

                     =15

Hence, the answer is 15.

Answer:-

Explanation :-

⬤•━━━━━━━━━━[tex] \sf \: \: \: x= \frac{(mx_2+nx_1)}{(m+n)} ,y= \frac{(my_2+ny_1)}{(m+n)} \\ \\