Math, asked by ronit2401, 1 year ago

Factorise a²(b + c) – (b + c)^3​

Answers

Answered by digantc
1

Answer:

(b+c)(a^2-b^2-c^2-2bc)

Step-by-step explanation:

a^2(b+c)-(b+c)^3

=> a^2(b+c)-(b+c)(b+c)(b+c)

Take (b+c) as common

=> (b+c){a^2-(b+c)(b+c)}

=> (b+c){a^2-(b+c)^2}

=> (b+c)[a^2-{(b)^2+(c)^2+2(b)(c)}]           [(a+b)^2=a^2+b^2+2ab]

=> (b+c)(a^2-b^2-c^2-2bc)


ronit2401: but the answer is. wrong
digantc: How?
ronit2401: a^2 (b+c) - (b+c) ^3
ronit2401: (b+c) (a-(b+c) (a+(b+c)
ronit2401: (b+c) (a-b-c) (a+b+c)
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