Question

factorise a2 + BC + AB + AC

Answer 1

Solution :

a² + bc + ab + ac

Rearranging the terms , we get

= a² + ab + ac + bc

= ( a×a + a×b )+( a×c+b×c )

Take a and c common in

first and second brackets

respectively, we get

= a( a + b ) + c( a + b )

Again take ( a + b )

common , we get

= ( a + b )( a + c )

••••

Answer 2

(a+b) (a+c)

It is the answer of this question I think