Question

Factorise a²b²-6abc+9c²​

Answer 1

Step-by-step explanation:

a²b²-6abc+9c²

We have to use the identity a² - 2ab + b² = (a-b)²

→ (ab)² - 2 × ab × 3c + (3c)²

→ (ab - 3c)²

or (ab - 3c) (ab - 3c)