Question

Factorise:
a³+3a²b+3ab²+b³-8



Please help me out in this question..(>_<)​

Answer 1

Answer:

• (a+b-2) [(a+b)(a+b+2)+4]

Step-by-step explanation:

(a + b)³ = a³ + b³ + 3ab² + 3a²b

=> a³ + 3a²b + 3ab² + b³ - 8

=> (a + b)³ - 8

> a³ - b³ = ab (a2 + ab + b2)

> a = a + b

> b = 8

Now,

=> a³ + 3a²b + 3ab² + b³ - 8

=> (a + b - 2) [(a + b)² + 2(a + b) + 2²]

$\boxed{\pink{ => (a + b - 2) [(a + b) (a + b + 2) + 4]}}$

Answer 2

Answer:

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