Question

Factorise: a³+64b³ plz factorise this​

Answer 1

Answer:

(a+4b)(a²+16b²-4ab)

Step-by-step explanation:

a³+64b³

= (a)³+(4b)³

= (a+4b)(a²+16b²-4ab)

using formula x³+y³ = (x+y)(x²+y²-xy)

Answer 2

Question:

Factorise: a³+64b³

Answer:

$= > {a}^{3} + 64 {b}^{3}$

$= > (Identity: {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} ) )$

By using appropriate identity,.

$= > {(a)}^{3} + {(4b)}^{3}$

$= > (a + 4b)( {a}^{2} - 4ab + {b}^{2} )$