Question

factorise

ab^2 + (a - 1) b - 1

Answer 1

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ab² + ( a - 1 ) b - 1

= ab² + ab - b - 1 [ using distributing property ]

= ab ( b + 1 ) - 1 ( b + 1 )

Take ( b + 1 ) is as common factor

= ( b + 1 ) ( ab - 1 )

Therefore,

( b + 1 ) , ( ab - 1 ) are two factors.

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Answer 2

Answer:

ab² + ( a - 1 ) b - 1

= ab² + ab - b - 1 [ using distributing property ]

= ab ( b + 1 ) - 1 ( b + 1 )

Take ( b + 1 ) is as common factor

= ( b + 1 ) ( ab - 1 )

Therefore,

( b + 1 ) , ( ab - 1 ) are two factors.

Step-by-step explanation:

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