factorise : ab^2-(a-b)b-c
Answers
Answered by
2
Best Answer: a^2 - b^2 ≡ (a + b)(a - b)
a^2 - b^2 + ac - bc
= (a^2 - b^2) + (ac - bc)
= (a + b)(a - b) + c(a - b)
= (a - b)[(a + b) + c]
= (a - b)(a + b + c)
a^2 - b^2 + ac - bc
= (a^2 - b^2) + (ac - bc)
= (a + b)(a - b) + c(a - b)
= (a - b)[(a + b) + c]
= (a - b)(a + b + c)
hasnath:
thxs alot .................!
Do you like math..?
yes but not much
i like commercial and algebra only
Answered by
0
ab^2-(a-b)b-c
a^2 - b^2 + ac - bc
= (a^2 - b^2) + (ac - bc)
= (a + b)(a - b) + c(a - b)
= (a - b)[(a + b) + c]
= (a - b)(a + b + c)
Similar questions