Question

Factorise ab^3+bc^3+ca^3+a^2b^2c^2-a^3b^2-b^3c^2-c^3a^2-abc

Answer 1

Answer:$(a^2-b)(b^2-c)(c^2-a)$

Step-by-step explanation:

$ab^3+bc^3+ca^3+a^2b^2c^2-a^3b^2-b^3c^2-c^3a^2-abc\\ \\ =>ab^3-a^3b^2+bc^3-c^3a^2+ca^3-abc+a^2b^2c^2-b^3c^2\\ \\=>ab^2(b-a^2)+c^3(b-a^2)-ca(b-a^2)-b^2c^2(b-a^2)\\ \\ =>(b-a^2)(ab^2+c^3-ca-b^2c^2)\\ \\ =>(b-a^2)(ab^2-b^2c^2+c^3-ca)\\ \\=> (b-a^2)(b^2(a-c^2)-c(a-c^2))\\ \\=>(b-a^2)(b^2-c)(a-c^2)\\ \\=>(a^2-b)(b^2-c)(c^2-a)$

Answer 2

Answer:

see above picture

Step-by-step explanation:

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