Question

factorise:ab(x^2+y^2)+xy(a^2+b^2)​

Answer 1

Answer:

ab ( x^2 + y^2) - xy ( a^2 + b^2)

= abx^2 + aby^2 - xya^2 - xyb^2

= abx^2 - xya^2 + aby^2 - xyb^2

= ax ( bx - ay) + by ( ay - bx)

= ax ( bx - ay) - by ( bx - ay)

= (ax - by) (bx - ay)

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Step-by-step explanation:

Answer 2

answer:-

ab ( x^2 + y^2) - xy ( a^2 + b^2)

ab ( x^2 + y^2) - xy ( a^2 + b^2)= abx^2 + aby^2 - xya^2 - xyb^2

ab ( x^2 + y^2) - xy ( a^2 + b^2)= abx^2 + aby^2 - xya^2 - xyb^2= abx^2 - xya^2 + aby^2 - xyb^2

ab ( x^2 + y^2) - xy ( a^2 + b^2)= abx^2 + aby^2 - xya^2 - xyb^2= abx^2 - xya^2 + aby^2 - xyb^2= ax ( bx - ay) + by ( ay - bx)

ab ( x^2 + y^2) - xy ( a^2 + b^2)= abx^2 + aby^2 - xya^2 - xyb^2= abx^2 - xya^2 + aby^2 - xyb^2= ax ( bx - ay) + by ( ay - bx)= ax ( bx - ay) - by ( bx - ay)

ab ( x^2 + y^2) - xy ( a^2 + b^2)= abx^2 + aby^2 - xya^2 - xyb^2= abx^2 - xya^2 + aby^2 - xyb^2= ax ( bx - ay) + by ( ay - bx)= ax ( bx - ay) - by ( bx - ay)= (ax - by) (bx - ay)

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