factorise ab²-bc-ab+c
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"ab²-bc-ab+c
=> ab (b - 1) - c (b-1)
=> (b-1) (ab-c)
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Answered by
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Answer:
( ab-c ) ( b-1 )
Step-by-step explanation:
Take common ,
=b( ab-c ) - 1 ( ab-c )
= ( ab-c ) ( b-1 )
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