Question

Factorise: abx2 +(b2-ac)x-bc = 0

Answer 1

HEY DEAR ...

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Consider, abx2 +(b2-ac)x-bc = 0

 ⇒ abx2 + b2x – acx – bc = 0

 ⇒ bx (ax + b) – c(ax + b) = 0 

⇒ (ax + b)(bx – c) = 0


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HOPE , IT HELPS ... ✌️

Answer 2

The Solution :

${abx}^{2} + ( {b}^{2} - ac)x - bc = 0 \\ = ab {x}^{2} + {b}^{2} x - acx - bc = 0 \\ = bx(ax + b) - c(ax + b) = 0 \\ = (bx - c)(ax + b) = 0$