Question

Factorise and divide

10y(6y+21) by 5(2y+7) by (y^2+7y+10) by (y+5)​

Answer 1

Answer:

${10y(6y + 21)} = 10y \times 3(2y + 7) = 30(2y + 7)$

now,

$\frac{30(2y + 7)}{5(2y + 7)} = 6$

again,

$\frac{6}{ {y}^{2} + 7y + 10} = \frac{6}{ {y}^{2} + 5y + 2y + 10 } = \frac{6}{y(y + 5) + 2(y + 5)} = \frac{6}{(y + 5)(y + 2)}$

and lastly,

$\frac{ \frac{6}{(y + 5)(y + 2)} }{y + 5} = \frac{6}{(y + 5)(y + 2)} \times \frac{1}{y + 5} = \frac{6}{(y + 5) ^{2}(y + 2) }$