Question

factorise and divide: 4lm(m^2+6m-16)÷2l(m+8)

Answer 1

4lm(m^2+8m-2m-16)/2l(m+8)
4lm(m(m+8)-2(m+8))/2l(m+8)
4lm(m+8)(m-2)/2l(m+8)
4lm(m-2)/2l. (m+8) is deleted.
m(m-2)
m^2-2m. is the answer.

Answer 2

Answer: $2m(m-2)$

Step-by-step explanation:

To simplify the given expression first we factorize: $m^2+6m-16$, we get

$m^2+6m-16\\=m^2+8m-2m-16\\=m(m+8)-2(m+8)\\=(m+8)(m-2)$

Now, we simplify the given expression by using the above factorization.$\frac{4lm(m^2+6m-16)}{2l(m+8)}\\\\=\frac{2m[(m+8)(m-2)]}{(m+8)}\\\\=\frac{2m(m-2)}{1}=2m(m-2)$