Question

factorise and divide 4yz(z²+6z-16)/2y(z+8)​

Answer 1

Answer:

Answer

4yz(z2+6z−16)÷2y(z+8)

2y(z+8)4yz(z2+8z−2z−16)

z+82z(z(z+8)−2(z+8))  ⇒(z+8)2z[(z+8)(z−2)]

2z(z−2)=2z2−4z.