Question

factorise and hence find the roots of given quadratic equation
$2 {x}^{2} - x - 6 = 0$
​

Answer 1

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆ }}}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-factorise

${2x}^{2} - x - 6 = 0$

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$➾2 {x}^{2} - x - 6 = 0$

$➾2 {x}^{2} - 3x + 2x - 6 = 0$

$➾2x(x - 3) + 2(x - 3) = 0$

$➾(2x + 2)(x - 3) = 0$

$➾2x + 2 = 0$

$➾2x = - 2$

$➾x = - 1$✓

$➾x - 3 = 0$

$➾x = 3$✓

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answer 2

$2 {x}^{2} - x - 6 = 0 \\ 2 {x}^{2} - 4x + 3x - 6 = 0 \\ 2x(x - 2) + 3(x - 2) = 0 \\ (x - 2)(2x + 3) = 0 \\ x - 2 = 0 \: and \: 2x + 3 = 0 \\ x = 2 \: and \: x = - \frac{3}{2}$