factorise answar 20a^2-45b^2
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Answered by
2
Here is your Answer,
By Using identity ,
a²-b²= ( a+b)(a-b)
Given , = 20a²-45b²
It can be written as ,
= (2√5a)²-(3√5b)²
Here a= (2√5a)
b= (3√5b)
= (2√5a - 3√5b)(2√5a +3√5b)
Hope this helps you....✌^_^
By Using identity ,
a²-b²= ( a+b)(a-b)
Given , = 20a²-45b²
It can be written as ,
= (2√5a)²-(3√5b)²
Here a= (2√5a)
b= (3√5b)
= (2√5a - 3√5b)(2√5a +3√5b)
Hope this helps you....✌^_^
Swarup1998:
Nice answer! (:
Answered by
2
HEYA MATE ,HERE IS UR ANSWER ____________________________
20a^2-45b^2
= (2root5a)^2-(3root5b)^2
using identity a^2-b^2=(a+b)(a-b)
= (2root5a+3root5b)(2root5a-3root5b)
__________HOPE THE ANSWER HELPS YOU. ☆☆____☆BE BRAINLY ☆☆☆☆_______☆☆☆
20a^2-45b^2
= (2root5a)^2-(3root5b)^2
using identity a^2-b^2=(a+b)(a-b)
= (2root5a+3root5b)(2root5a-3root5b)
__________HOPE THE ANSWER HELPS YOU. ☆☆____☆BE BRAINLY ☆☆☆☆_______☆☆☆
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