factorise (ax+by)²+(bx-ay)²
tenz:
plsss show me the solution
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Answered by
177
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a²x²+b²y²+b²x²+a²y²
x²(a²+b²)y²(a²+b²)
(x²+y²)(a²+b²):ans....
:)
if yes..
mark as brainliest
a²x²+b²y²+b²x²+a²y²
x²(a²+b²)y²(a²+b²)
(x²+y²)(a²+b²):ans....
:)
Attachments:
answer is (a²+b²)(x²+y²)
yes...
by taking comman...sorry
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Soooo grateful yaar
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its Priyavi
O sorry
Answered by
56
(ax^2 + by^2 + 2axby) + ( bx^2 + ay^2 - 2bxay)
= ax^2 + by^2 + 2axby + bx^2 + ay^2 - 2bxay
= ax^2 + by^2 + bx^2 + ay^2 ( + 2axby and - 2bxay gets cancelled)
= ax^2 + bx^2 + ay^2 + by^2
= x^2( a + b) + y^2 ( a + b)
= (x^2 + y^2 ) + (a+b)
hope this helps.
= ax^2 + by^2 + 2axby + bx^2 + ay^2 - 2bxay
= ax^2 + by^2 + bx^2 + ay^2 ( + 2axby and - 2bxay gets cancelled)
= ax^2 + bx^2 + ay^2 + by^2
= x^2( a + b) + y^2 ( a + b)
= (x^2 + y^2 ) + (a+b)
hope this helps.
2nd step comes from the formula of (a+b)^2 and (a-b) ^2
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