Factorise (b+c-a)(c+a-b)(a+b-c)+8abc
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Answer:
(a+b)(b+c)(c+a)≥8abc
Step-by-step explanation:
This is true only if a,b,c≥0
Apply AM≥GM for a,b
2a+b≥ab→ eqn 1
Apply AM≥GM for b,c
2b+c≥bc→ eqn 2
Apply AM≥GM for c,a
2c+a≥ca→ eqn 3
Multiply corresponding sides of eqn 1,2,3
⇒(a+b)(b+c)(c+a)≥8abc
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