factorise both a and b first x2+6x+8 second question x2+x-12
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Answered by
3
(a) x^2 + 6x + 8
= x^2 + 2x + 4x + 8
= x(x+2) + 4(x+2)
= (x+2)(x+4).
(b) x^2 + x - 12.
= x^2 - 3x + 4x - 12
= x(x -3) + 4(x-3)
= (x-3)(x+4).
Hope this helps!
= x^2 + 2x + 4x + 8
= x(x+2) + 4(x+2)
= (x+2)(x+4).
(b) x^2 + x - 12.
= x^2 - 3x + 4x - 12
= x(x -3) + 4(x-3)
= (x-3)(x+4).
Hope this helps!
Answered by
3
x²+6x+8
x²+4x+2x+8
x(x+4)+2(x+4)
(x+2)(x+4)
2.
x²+x-12
x²+4x-3x-12
x(x+4)-3(x+4)
(x-3)(x+4)
hope this helps
x²+4x+2x+8
x(x+4)+2(x+4)
(x+2)(x+4)
2.
x²+x-12
x²+4x-3x-12
x(x+4)-3(x+4)
(x-3)(x+4)
hope this helps
aryan1191:
wlcm
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