Question

factorise by completing the squares 1/3x^2-2x-9​

Answer 1

Answer:

$(x - 9)( \frac{1}{3}x + 1)$

Step-by-step explanation:

${ \frac{1}{3} }x^{2} - 2x - 9 \\ = > \frac{1} {3} {x}^{2} - 3x + x -9 \\ \ \: \: \: \: \: \: = > \frac{1}{3}x(x - 9) + 1(x - 9) \\ = > \: \:(x - 9)( \frac{1}{3}x + 1)$

Hope it helps you.