Question

Factorise by regrouping terms:

1)ab-a+b-1
2)6ab-b^2-12ac-2bc
3)ar+br+at+bt
4)x^3-3x^3+x-3
5)ab^2-bc^2-ab+c^2

With Steps

Answer 1

Answer:

1)=ab-a+b-1

Step-by-step explanation:

(a-a)-(b+b)-1

a(1-1)-b(1+1)-1

(a-b)(1+1)-1

Ans=(a-b)(1+1)-1

Answer 2

Answer:

1) a(b-1)+ 1(b-1) = (a+1) (b-1)

2) 6ab+b² - 12ac-2bc

= 6ab-12ac+b²-2bc

= 6a(b-2c) + b(b-2c)

= (b-2c) (6a+b)

3) ar+br+at+bt

=r(a+b) +t(a+b)

= (a+b) (r+t)

4) x³-3x³+x-3

= -2x²+x-3

= -2x²+3x-2x-3

= x(-2x+3) + 1(2x-3)

= (x+1) (-2x+3)

5) ab²-bc²-ab+c²

= b(ab-c²) - 1(ab-c²)

= (ab-c²) (b-1)

Hope you get my answer.