Factorise by splitting middle terms
6 x^3 +25x^2+24x
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Answered by
1
6x³+25x²+24x
x(6x² + 25x + 24)
x(6x² + 9x + 16x + 24)
x[3x(2x+3) + 8(2x + 3)]
(x)(2x+3)(3x+8)
x(6x² + 25x + 24)
x(6x² + 9x + 16x + 24)
x[3x(2x+3) + 8(2x + 3)]
(x)(2x+3)(3x+8)
Answered by
0
6x^3 + 25x^2 +24x= x[6x^2 +25x+24]
=x[6x^2 +16x+9x+24]
=x[2x(3x+8)+3(3x+8)]
=x[(2x+3)(3x+8)]
x=0, x =-3/2 or x=-8/3
=x[6x^2 +16x+9x+24]
=x[2x(3x+8)+3(3x+8)]
=x[(2x+3)(3x+8)]
x=0, x =-3/2 or x=-8/3
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