Question

factorise by splitting the middle term
2x^2+6x-8​

Answer 1

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$2 {x}^{2} + 6x - 8 \\ 2 {x}^{2} - 2x + 8x - 8 \\ 2x(x - 1) + 8(x - 1) \\ (x - 1)(2x + 8)$

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Answer 2

$\huge\purple {♡}\pink { Answer}\purple</p><p>{♡}$

$2 {x}^{2} + 6x - 8$

$2( {x}^{2} + 3x - 4)$

$2( {x}^{2} + 4x - x - 4)$

$2(x(x + 4) - 1(x + 4))$

$2(x + 4)(x + 1)$